(12p^2+6p-6)/4(p+1)^2/(6p-3)/(2p+10)

Solution for (12p^2+6p-6)/4(p+1)^2/(6p-3)/(2p+10) equation:

D( p )

2*p+10 = 0

6*p-3 = 0

2*p+10 = 0

2*p+10 = 0

2*p+10 = 0 // - 10

2*p = -10 // : 2

p = -10/2

p = -5

6*p-3 = 0

6*p-3 = 0

6*p-3 = 0 // + 3

6*p = 3 // : 6

p = 3/6

p = 1/2

p in (-oo:-5) U (-5:1/2) U (1/2:+oo)

((((12*p^2+6*p-6)/4)*(p+1)^2)/(6*p-3))/(2*p+10) = 0

((12*p^2+6*p-6)*(p+1)^2)/(4*(6*p-3)*(2*p+10)) = 0

12*p^2+6*p-6 = 0

6*(2*p^2+p-1) = 0

2*p^2+p-1 = 0

DELTA = 1^2-(-1*2*4)

DELTA = 9

DELTA > 0

p = (9^(1/2)-1)/(2*2) or p = (-9^(1/2)-1)/(2*2)

p = 1/2 or p = -1

6*(p+1)*(p-1/2) = 0

(6*(p+1)^3*(p-1/2))/(4*(6*p-3)*(2*p+10)) = 0

( p+1 )

p+1 = 0 // - 1

p = -1

( p-1/2 )

p-1/2 = 0 // + 1/2

p = 1/2

p in { 1/2} 

p in { -1, -1, -1 }